(Proof) For positive numbers \(a,b\) and \(H\), suppose a real
number \(r\) exists such that
\(a=H+\dfrac{a}{r}\) and \(H=b+\dfrac{b}{r}\).
\((\mathrm{A})\)
Then, \(a\ne b\) and
\(\dfrac{a-H}{a}= \fbox{\(\;(\alpha)\;\)}\)
\((\mathrm{B})\)
therefore \(H=\fbox{\(\;(\beta)\;\)}\).
Conversely, let \(a\) and \(b\) be positive numbers such that \(a\ne
b\). Let \(H=\fbox{\(\;(\beta)\;\)}\). Then \((\mathrm{B})\) holds
and \(\dfrac{a-H}{a}\ne 0\).
From \((\mathrm{B})\), let \(\dfrac{a-H}{a}=\dfrac{1}{r}\). Then
\((\mathrm{A})\) also holds.
Therefore, for positive numbers \(a, b\) and \(H\),
‘\(a\ne b\) and \(H=\fbox{\(\;(\beta)\;\)}\)’ is
\(\fbox{\(\;(\gamma)\;\)}\) for the existence of a real number \(r\)
such that \((\mathrm{A})\) holds.
In the proof above, what are appropriate for \((\alpha), (\beta)\) and
\((\gamma)\) in this order?